-2(n^2-8n)=8(n+1)

Solution for -2(n^2-8n)=8(n+1) equation:

-2(n^2-8n)=8(n+1)

We move all terms to the left:

-2(n^2-8n)-(8(n+1))=0

We multiply parentheses

-2n^2+16n-(8(n+1))=0


We calculate terms in parentheses: -(8(n+1)), so:

8(n+1)

We multiply parentheses

8n+8

Back to the equation:

-(8n+8)


We get rid of parentheses

-2n^2+16n-8n-8=0

We add all the numbers together, and all the variables

-2n^2+8n-8=0

a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-8}{-4}=+2$